Asked by Nic
The velocity of a 2.5 kg block sliding down a frictionless inclined plane is found to be 1.58 m/s. 1.40 s later, it has a velocity of 7.32 m/s.
What is the angle of the plane with respect to the horizontal (in degrees)?
What is the angle of the plane with respect to the horizontal (in degrees)?
Answers
Answered by
bobpursley
acceleration= change velocity/time
force down= mass*acceleration
mgSinTheta= m*a
solve for theta.
force down= mass*acceleration
mgSinTheta= m*a
solve for theta.
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