or
sin (255°) = sin (180° + 75°)
= - sin 75° [The terminal side of the angle lies in quadrant III, so the sine function is negative.]
= - sin (45° + 30°)
= - (sin 45°cos 30° + cos 45°sin 30°) [Use sin (A + B) = sin A cos B + cos A sin B.]
= - [( Square root of (2) /2)( Square root of (3) /2) + ( Square root of (2) /2)(1/2)]
= - ( Square root of (6) + Square root of (2) /4) = - Square root of (6) - Square root of (2) /4
is this correct?
sin 255degrees
225 = 180 + 45
sin(225) = sin(180 + 45) = sin(180)cos(45) + cos(180)sin(45)
sin(225) = 0 + (-1)(sqrt2/2)
sin(225) = -(sqrt2)/2
4 answers
Your first two lines make it unclear whether you want sin 255 or sin 225.
255 i guess that makes the first 1 wrong.
sin 255 should be
-(1/4)[sqrt6 + sqrt2]
-(1/4)[sqrt6 + sqrt2]