match
2x^2 - 3x - 2 = 0 with
ax^2 + bx + c = 0
so a=2, b=-3, c=-2
the formula says
x = (-b ±√(b^2 - 4ac))/(2a)
substitute the above values and simplify
(did you get x=2, x=-1/2 ?)
Solve 2x(squared)-3x-2=0 using the quadratic formula. Can someone explain this to me please?
1 answer