Asked by Ann
I don't understand this question.
Three weights are attached to the corners of an equilateral triangle with a side length 10 cm. Measured from the bottom left corner, what is the center of mass of this object if M1 = 0.1 kg, M2 = 0.2 kg, and M3 = 0.3 kg? and M2 is on the left corner, M1 is at the top and M3 is on the right corner.
Three weights are attached to the corners of an equilateral triangle with a side length 10 cm. Measured from the bottom left corner, what is the center of mass of this object if M1 = 0.1 kg, M2 = 0.2 kg, and M3 = 0.3 kg? and M2 is on the left corner, M1 is at the top and M3 is on the right corner.
Answers
Answered by
bobpursley
draw a grid, put the triangle on it, locate the coordinates of the three corners.
I get (0,0), (10,0), and (5,17.3/2) check those.
Now the cg for the x coordinate
cg*.6=.1*0+.2*5+.3*10
cg=4/.6=6.66
and the cg for the y is
cg*.6=.2*17.3/2
and cg = 2.88
cg(6.66,2.88) check all that math. I did most of it in my head.
I get (0,0), (10,0), and (5,17.3/2) check those.
Now the cg for the x coordinate
cg*.6=.1*0+.2*5+.3*10
cg=4/.6=6.66
and the cg for the y is
cg*.6=.2*17.3/2
and cg = 2.88
cg(6.66,2.88) check all that math. I did most of it in my head.
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