An object is swinging from a point that is horizontal compared to the lowest point the object will reach (where the rope is vertical). If the length of the rope is 2 meters and the mass of the object is 30 kg, what is the tension in the rope at the bottom of the swing?

Question

Need Step by step solution!

Answer 1

Drop in potential energy from horizontal to vertical orientation is
2 meters *m* g

This must equal 1/2 m v^2, because velocity is zero when the rope is horizontal. This means that:

v^2 = 4 meters*g --->

v^2/(2meters) = 2 g is the centripetal acceleration.

Newton's second law:

F = m a

applied to the object gives:

-mg + T = 2mg

where T is the tension and we take the positive direction to be upward.

The tension is thus T = 3 m g.

Answer 2

Is it vertical vs. Horizontal energy to get the Acceleration?

Answer 3

NVM you are relating GPE for Horizontal to KE of Horizontal.