Asked by m
addition method:3x-5y=-2 and 5y-2x=-2
how would I solve it since they are not together?
how would I solve it since they are not together?
Answers
Answered by
MathMate
These simultaneous equations can be solved most of the time by either substitution or by elimination. We will try elimination here, since I see 5y in both equations.
3x-5y=-2....(1)
5y-2x=-2....(2)
Rearrange to line up x and y in columns
3x-5y=-2...(1a)
-2x+5y=-2...(2a)
Add the two equations:
3x-2x -5y+5y = -2 -2
simplify to get
x = -4 ... (3)
Substitute (3) into (1) to get
3(-4)-5y=-2
-5y = -2 + 12
-5y = 10
y = 10 / (-5) = -2 ..(4)
(3) and (4) give the final answer, but we still have one more step to do: check!
Substitute (3) and (4) into (1) and (2) to get
3(-4)-5(-2)
=-12+10
=-2 from (1) OK
5(-2)-2(-4)
=-10+8
=-2 from (2) OK
3x-5y=-2....(1)
5y-2x=-2....(2)
Rearrange to line up x and y in columns
3x-5y=-2...(1a)
-2x+5y=-2...(2a)
Add the two equations:
3x-2x -5y+5y = -2 -2
simplify to get
x = -4 ... (3)
Substitute (3) into (1) to get
3(-4)-5y=-2
-5y = -2 + 12
-5y = 10
y = 10 / (-5) = -2 ..(4)
(3) and (4) give the final answer, but we still have one more step to do: check!
Substitute (3) and (4) into (1) and (2) to get
3(-4)-5(-2)
=-12+10
=-2 from (1) OK
5(-2)-2(-4)
=-10+8
=-2 from (2) OK
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