Asked by valentina
How many grams of Lead (II) Nitrate are required to make a 350mL solution of 2.5M Pb2+?-
Answers
Answered by
DrBob222
Moles Pb = moles Pb(NO3)2.
How many moles Pb(NO3)2 do you need? moles = M x L = ??
moles = grams/molar mass
Solve for grams.
How many moles Pb(NO3)2 do you need? moles = M x L = ??
moles = grams/molar mass
Solve for grams.
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