Distance D = Rate R * Time T
60 = rate for car
T = time for car
60T = distance for car
40 = rate for bus
T + 1.50 = rate for bus
40(T + 1.50) = distance for bus
Distances are equal
60T = 40(T + 1.50)
Solve for T, time in hours for car to overtake the bus
R + 40 = rate for train
How long will it take a car traveling at 60 mph to overtake a bus traveling at 40 mph if the bus had a 1.5 hour head start?
4 answers
At the point of overtaking they must have gone the same distance, d
then the difference in their times must have been 1.5 hrs.
d/40 - d/60 = 1.5
times 120
3d - 2d = 180
d = 180
can you take it from there?
then the difference in their times must have been 1.5 hrs.
d/40 - d/60 = 1.5
times 120
3d - 2d = 180
d = 180
can you take it from there?
Ignore this line from my post above,
"R + 40 = rate for train"
"R + 40 = rate for train"
25