Asked by arty
f'(x^2)^2=?
Answers
Answered by
MathMate
f'(x²)
=d(x²)/dx
=2x (by the power rule)
so
(f'(x²)²
=(2x)²
=4x²
=d(x²)/dx
=2x (by the power rule)
so
(f'(x²)²
=(2x)²
=4x²
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