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Question

(4y^2)^5
__________
y ^-3
14 years ago

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Helper
Julie, because of formatting please type division problems as follows (using "/" for division).

If this is your problem,
((4y^2)^5)/y^-3

1024y^10/y^-3 = 1024y^13

Subtract the exponents, 10 - (-3) = 13

Or, 1024y^10/(1/y^3)
Invert the denominator and multiply,
1024y^10 * y^3 = 1024y^13

Remember, y^-3 = 1/y^3
14 years ago

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