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Asked by Julie

Complex Fractions

_1_ - _2_
x^2 3

____________

_1_ - _5_
x 6
14 years ago

Answers

Answered by Julie
3 is supposed to be the denominator of 2
6 is supposed to be the denominator of 5
14 years ago
Answered by Reiny
So I see it as

(1/x^2 - 2/3) / (1/x - 5/6)
= (3-2x^2)/(3x^2) / (6x)/(6-5x)
= (3 - 2x^2)/(3x^2) (6x)/(6-5x)
= 2(3-2x^2)/(x(6-5x))
or
= 2(2x^2 - 3)/(x(5x - 6))
14 years ago

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