f(x)=3x^ln(x),

find f '(9).

i can't find the answer :(

I got 3x^lnx(((ln(lnx))/x)+ 1/lnx)

1 answer

F(x) = 3X^ln(x).

F'(x) = (3lnx)(X^(lnx-1),
F'(9) = (3*ln9)(9^(ln9-1),
F'(9) = (3*2.1972)(9^(2.1972-1),
F'(9) = (6.5917)(9^1.1972),
F'(9) = (6.5917)(13.8817),
F'(9) = 91.5040.
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