Asked by henry baliz
let f(x)= -x^2 - 1. evaluate f(x)at x=6, -6
Answers
Answered by
MathMate
f(x)=-x^2-1
f(6)=-(6)^2-1=-36-1=-37
f(-6)=-(-6)^2-1=-36-1=37
So we see that for this particular function, f(6)=f(-6).
In fact, since f(x) is an even function (consisting of even powers of x), this property of f(x)=f(-x) is true for all values of x.
You can try out other pairs, such as f(2) and f(-2) to verify this property.
f(6)=-(6)^2-1=-36-1=-37
f(-6)=-(-6)^2-1=-36-1=37
So we see that for this particular function, f(6)=f(-6).
In fact, since f(x) is an even function (consisting of even powers of x), this property of f(x)=f(-x) is true for all values of x.
You can try out other pairs, such as f(2) and f(-2) to verify this property.
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