Asked by Anonymous
                Solve the inital value problem for y as a function of x given: dy/dx=2x-6 with an inital condition of y=4 when x=1. 
antiderivative->x^2-6x+c
4=1^2-6(1)+c
c=9
y-x^2-6x+9
            
        antiderivative->x^2-6x+c
4=1^2-6(1)+c
c=9
y-x^2-6x+9
Answers
                    Answered by
            Reiny
            
    see previous solution
    
                    Answered by
            Anonymous
            
    Do you mean c=9? 
    
                    Answered by
            Reiny
            
    yes, your solution is correct, except write it up this way:
dy/dx = 2x-6
y = x^2 - 6x + c and then proceed as you did before
    
dy/dx = 2x-6
y = x^2 - 6x + c and then proceed as you did before
                    Answered by
            Anonymous
            
    I didn't realize I put y- instead of y=. So, you mean write it y=x^2-6x+9?
    
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