Asked by Anonymous
a .250kg block of aluminum is heated to 100 C and then dropped into .60 kg of water that is initially at 20C. What is the equilibrium temperature of the system? The specific heat of aluminum is .22 kcal/kg C
Answers
Answered by
bobpursley
The sum of the heats gained is zero.
heatgainedAl+heatgainedWater=0
.250*.22*(Tf-00)+.6*c*(Tf-20)=0
solve for Tf
heatgainedAl+heatgainedWater=0
.250*.22*(Tf-00)+.6*c*(Tf-20)=0
solve for Tf
Answered by
Anonymous
thanks!
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