50 mL x 0.01M Ba(OH)2 = 0.5 millimoles.
150 mL x 0.01 M HNO3 = 1.5 mmols.
....Ba(OH)2 + 2HNO3 ==> Ba(NO3)2 + 2H2O
I...0..........1.50........0.........0
added 0.5...............................
C....-0.5......-1.00......0.5........
E.......0.......0.5.........0.5........
(HNO3) = 0.5 millimols/200 mL = 0.0025 M
I work in millimoles when there are so many zeros. For example, for the Ba(OH)2 part.
mols = M x L = 0.01 x 0.050 = 0.0005 mol.
But millimols = 50 x 0.01 = 0.500.
You can change to mols in the above if you wish by dividing millimoles by 1000.
50.0mL of 0.01M Ba(OH)2 is added to 150.0mL of 0.01M HNO3. What is the new pH of the solution?
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