$50,000 that was invested in 1970 was worth $134,100 in 1980. What annual interest rate did this investment earn in that 10 year period? Assume continous compounding.

Answer 1

solve
134 100 = 50 000(e^(10k)

e^(10k) = 134100/50000
10k = ln(134100/50000)

I don't have a calculator handy,
your k value should be a decimal, I will assume you can read the percentage rate from that.