50.0 mL of a 0.20 mol/L HCl reacts with 60.0 mL of 0.15 mol/L NaOH. What is the pH of the final solution?
I tried writing out the equation:
HCl + NaOH = Cl + NaH2O
Now, I am not sure of NaH2O is the right product or not..
However, I am still confused on how I can ifnd the final pH.
5 answers
yes it is had the same hw
Oh okay thanks!
But could you take me throught the steps to get to the final answer please? or at least lead me in the right direction ?
But could you take me throught the steps to get to the final answer please? or at least lead me in the right direction ?
ok did you happen to get 0.082 mol/L or 0.164 mol/L as possible concentrations?
Can anyone please help me out here?
I believe both of you are confused.
HCl + NaOH ==> NaOH + H2O
mols HCl = M x L = ?
mols NaOH = M x L = ?
You go through the math above and find HCl is greater mols than NaOH by 0.001
Then (HCl) = mols/L = 0.001/0.110
HCl + NaOH ==> NaOH + H2O
mols HCl = M x L = ?
mols NaOH = M x L = ?
You go through the math above and find HCl is greater mols than NaOH by 0.001
Then (HCl) = mols/L = 0.001/0.110