Asked by angelia
5/y-3=y+7/2y-6+1=
an equation with extraneou solution.
I need help with this problem
an equation with extraneou solution.
I need help with this problem
Answers
Answered by
drwls
Do you mean
5/(y-3) = [(y+7)/(2y-6)] + 1 ?
If not, put the parentheses where they belong. Otherwise, there are too many possible answers.
5/(y-3) = [(y+7)/(2y-6)] + 1 ?
If not, put the parentheses where they belong. Otherwise, there are too many possible answers.
Answered by
angelia
In the problem there are no parentheses
this how the problem is in the book.
5/y-3=y+7/2y-6+
5 over y-3= yplus seven over 2y-6 +1 there is no parenheses
this how the problem is in the book.
5/y-3=y+7/2y-6+
5 over y-3= yplus seven over 2y-6 +1 there is no parenheses
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