My calculation shows 17.89 L which I would round to 17.9L.
For mol = n you should have
27g Ne x (1 mol Ne/20g Ne) = 13.5 mol Ne. Showing the factor as I've shown it makes more sense than the way you do although yours is correct except for the K. (1 mol K should be 1 mol. The K is not needed.)
Then if you plug in P in atm, R in (L*atm/mol*K) and T in K, V comes out in L.
5. What volume would 27g of neon at 2 atm pressure and 50°C occupy?
I have solved the problem correctly, but I am not sure if I have the correct units on this conversion so that everything will cancel out. Also, is it right to have 20g Ne/1mole K? I seem to be missing something with the 20g Ne.
V = (27g Ne/20g Ne/1mole K)(0.08206 L atm)x(323K)/2 atm = 17.8L
2 answers
can you explain how to do t his i am confused