5. The ages of two sisters can be represented as consecutive odd integers.twelve years ago, the sum of their ages was 8.how old I am?

Question

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Answer 1

Let the age of the younger sister be x and the age of the older sister be x + 2.

Twelve years ago, the age of the younger sister was x - 12 and the age of the older sister was x + 2 - 12 = x - 10.
The sum of their ages twelve years ago was (x - 12) + (x - 10) = 8.

Simplifying the equation:
2x - 22 = 8
2x = 30
x = 15

Therefore, the younger sister is currently 15 years old and the older sister is 17 years old.