5) suppose in the previous question when timmy is sitting at rest he has 40j of GPE then his dad geves timmy a push when his dad lets go Timmy has 60j of GPE and 12J of KE

Question

a) befor his dad pushed him GPE= 40J Ke= 0J TE=40J
b) immedialtey after his dad pushes him GPE= 60 KE= 120 TE=180
C) How much work did timmys dad do when he pushed Timmy? 180J-40J=140J

D) At the top of Timmys path
GPE=180j KE=oJ TE= 180j
E) He swing back down through the bottom of his path
GPE=oj KE=180j TE=180j
F) Timmy jumps off the swing just befor he lands
GPE=oj KE=180j TE=180j

G) timmy hit the ground
GPE=oj KE=oj TE=oj
H) how much work does the ground do on (Didnt answer help please with letter h)

Answer 1

Nuts to these:
immedialtey after his dad pushes him GPE= 60 KE= 120 TE=180
C) How much work did timmys dad do when he pushed Timmy? 180J-40J=140J

nuts to these:
D) At the top of Timmys path
GPE=180j KE=oJ TE= 180j
E) He swing back down through the bottom of his path
GPE=oj KE=180j TE=180j
F) Timmy jumps off the swing just befor he lands
GPE=oj KE=180j TE=180j

H. at jumping off, he has zero gpe, but he has KE. The ground must have done that work to make the final KE zero.

After DAd swims him, dad must have done (60-40)J increase in GPE+ an additional 12j for the KE.