5 students are randomly seated along the side of a table. What is the probability that they are seated in order of age?
4 answers
What is 5! ?
5!=120
1/120= 0.0083
but the options are
0.1
0.054
0.0167
Impossible to determine
Am I missing something?
1/120= 0.0083
but the options are
0.1
0.054
0.0167
Impossible to determine
Am I missing something?
You are missing the fact that they could be ordered according to increasing or according to decreasing age.
Each would be ordered by age.
so prob = 2/120 = 1/60 = appr .0167
Each would be ordered by age.
so prob = 2/120 = 1/60 = appr .0167
Ah okay. Thanks!