Let's assume the number of phones without answering machines produced per day is x, and the number of phones with answering machines produced per day is y.
According to the problem, the company produces 600 phones per day, so we can create the first equation:
x + y = 600 (Equation 1)
The demand for phones with answering machines is twice as great as the demand for phones without answering machines. We can represent this by the equation:
y = 2x (Equation 2)
To solve this system of linear equations, we'll use the substitution method, where we solve one equation for one variable and substitute it into the other equation.
From Equation 2, we can solve for y:
y = 2x
Now, we substitute this value of y in Equation 1:
x + 2x = 600
3x = 600
Dividing both sides by 3, we get:
x = 200
Now that we have the value of x, we can substitute it back into Equation 2 to find y:
y = 2x
y = 2(200)
y = 400
So, the company should schedule 200 phones without answering machines and 400 phones with answering machines for production.
5. Solve each system of linear equation and explain any method you used:
-A company produces telephones at the rate of 600 per day. A customer survey indicates that the demand for phones with built in answering machines is twice as great as the demand for phones without the machines. If you are deciding the production quota for the day, how many phones with answering machines would you schedule for production? How many without answering machines would you make?
1 answer
1 answer