To determine the number of additional sessions (s) that David can schedule given that he wants to spend at most $700 on tutoring, we need to set up an inequality based on the cost structure.
The cost David incurs for the tutoring sessions is comprised of:
- An initial fee of $500
- An additional fee of $50 for each session he schedules
Thus, the total cost can be written as: \[ 500 + 50s \]
Since David wants to spend at most $700, we can set up the inequality: \[ 500 + 50s \leq 700 \]
Now let's review the given options:
- \( 50s + 500 > 700 \)
- \( 50s + 500 < 700 \)
- \( 50s + 500 \leq 700 \) (correct)
- \( 50s + 500 \geq 700 \)
The correct choice is: 50s + 500 ≤ 700
Now, we can find out how many additional sessions David can schedule.
To solve for s: \[ 500 + 50s \leq 700 \] Subtract 500 from both sides: \[ 50s \leq 200 \] Now, divide by 50: \[ s \leq 4 \]
Thus, David can schedule 4 additional sessions.