5. Match each ⭐ with a πŸ’Ž .

A card sort is on the screen. To start dragging a card, Tab to it and press M to mark it. Next, Tab to the card where you want to drop, and press J to join the two cards together. To unjoin the selected card from a group, press U.
3xβˆ’2 πŸ’Ž

1
x​ ⭐

3
x4​ ⭐

y3
x2​ ⭐

x2yβˆ’3 πŸ’Ž

x0 πŸ’Ž

xβˆ’2y3 πŸ’Ž

xβˆ’1 πŸ’Ž

xβˆ’3 πŸ’Ž

1
x3​ ⭐

3xβˆ’4 πŸ’Ž

3
x2​ ⭐

1 ⭐

To attach cards, drag it on TOP of each other until you see them CONNECT.

To detach, drag the BOTTOM card away.

x2
y3​

1 answer

To match each starred cards (⭐) with diamond cards (πŸ’Ž), we need to look for equivalent algebraic expressions based on exponents of \( x \) and \( y \).

Here’s how we can match them:

  1. \( \frac{1}{x} \) (⭐) can be matched with \( x^{-1} \) (πŸ’Ž) because \( \frac{1}{x} = x^{-1} \).

  2. \( \frac{3}{x^4} \) (⭐) can be matched with \( 3x^{-4} \) (πŸ’Ž) for the same reason: \( \frac{3}{x^4} = 3x^{-4} \).

  3. \( y^3x^2 \) (⭐) can be matched with \( x^2y^3 \) (πŸ’Ž) because these two expressions are equivalent regardless of the order (commutative property of multiplication).

  4. \( x^{-2}y^3 \) (⭐) can be matched with \( x^{-2}y^3 \) (πŸ’Ž) as they are the same expression.

  5. \( \frac{1}{x^3} \) (⭐) can be matched with \( x^{-3} \) (πŸ’Ž) since \( \frac{1}{x^3} = x^{-3} \).

  6. \( 1 \) (⭐) remains unmatched as there is no specific partner among diamonds that is equivalent.

  7. \( 3x^2 \) (⭐) can also remain unmatched as there is no specific partner among diamonds that is equivalent.

Therefore, the matches are:

  1. \( 1/x \) ⭐ matches (x^{-1}) πŸ’Ž
  2. \( 3/x^4 \) ⭐ matches (3x^{-4}) πŸ’Ž
  3. \( y^3x^2 \) ⭐ matches (x^2y^3) πŸ’Ž
  4. \( x^{-2}y^3 \) ⭐ matches (x^{-2}y^3) πŸ’Ž
  5. \( 1/x^3 \) ⭐ matches (x^{-3}) πŸ’Ž

Remaining unmatched cards are:

  • \( 1 \) ⭐
  • \( 3x^2 \) ⭐

You can now proceed with these matches as per the directions provided on the screen for the drag and drop action.