To match each starred cards (β) with diamond cards (π), we need to look for equivalent algebraic expressions based on exponents of \( x \) and \( y \).
Hereβs how we can match them:
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\( \frac{1}{x} \) (β) can be matched with \( x^{-1} \) (π) because \( \frac{1}{x} = x^{-1} \).
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\( \frac{3}{x^4} \) (β) can be matched with \( 3x^{-4} \) (π) for the same reason: \( \frac{3}{x^4} = 3x^{-4} \).
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\( y^3x^2 \) (β) can be matched with \( x^2y^3 \) (π) because these two expressions are equivalent regardless of the order (commutative property of multiplication).
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\( x^{-2}y^3 \) (β) can be matched with \( x^{-2}y^3 \) (π) as they are the same expression.
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\( \frac{1}{x^3} \) (β) can be matched with \( x^{-3} \) (π) since \( \frac{1}{x^3} = x^{-3} \).
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\( 1 \) (β) remains unmatched as there is no specific partner among diamonds that is equivalent.
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\( 3x^2 \) (β) can also remain unmatched as there is no specific partner among diamonds that is equivalent.
Therefore, the matches are:
- \( 1/x \) β matches (x^{-1}) π
- \( 3/x^4 \) β matches (3x^{-4}) π
- \( y^3x^2 \) β matches (x^2y^3) π
- \( x^{-2}y^3 \) β matches (x^{-2}y^3) π
- \( 1/x^3 \) β matches (x^{-3}) π
Remaining unmatched cards are:
- \( 1 \) β
- \( 3x^2 \) β
You can now proceed with these matches as per the directions provided on the screen for the drag and drop action.