To solve the equation 5(g-4)=7(2g+1), we will first distribute the numbers on both sides of the equation:
5g - 20 = 14g + 7
Next, we will group the terms with variable g on one side and the constant terms on the other side:
5g - 14g = 7 + 20
Combine like terms:
-9g = 27
To solve for g, we will divide both sides of the equation by -9:
-9g / -9 = 27 / -9
The -9s cancel out on the left side:
g = -3
Therefore, the solution to the equation 5(g-4)=7(2g+1) is g = -3.
5(g-4)=7(2g+1)
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