5. Concentration of 0.24L KMnO4 solution required to oxidize 2.7g of Oxalic Acid??? 5H2C2O4 (aq) + 6H+ + 2MnO4- (aq) --> 10CO2 (g) + 2 Mn2+(aq) +8H20 (l)
Molecular weight:
H2C2O4 = 2+24+64 = 90
2.7 g of oxalic acid is equivalent to
2.7/90=0.03 mole
Number of moles of KMnO4 required
=0.03*2/5=0.012 mole
let x=Concentration of KMnO4
then 0.24 l * x mole/l =0.012 mole
x=0.05 mole/l.
4.How many grams of calcium chloride can be prepared if a student uses 500g if calcium carbonate and 2.00L of a 4.00 Mol/L sodium chloride solution (Hydrochloric acid) in the reaction.??
CaCO3 + 2HCl -> CaCl2 + H2O
Molecular weight of calcium carbonate
= 40+12+48 = 100
500 g. = 500/100= 5 moles
HCl required for complete reaction with calcium carbonate
= 5*2/1=10 moles
Actual quantity of HCl used
=2 l. * 4 mol/l
=8 moles
Thus number of moles of CaCl2 produced
= 5*8/10=4
Weight of CaCl2 produced
= 4*(40+2*35.5)=444 g.
5. Concentration of 0.24L KMnO4 solution required to oxidize 2.7g of Oxalic Acid??? 5H2C2O4 (aq) + 6H+ + 2MnO4- (aq) --> 10CO2 (g) + 2 Mn2+(aq) +8H20 (l)
4.How many grams of calcium chloride can be prepared if a student uses 500g if calcium carbonate and 2.00L of a 4.00 Mol/L sodium chloride solution in the reaction.??
CaCO3 + 2HCl -> CaCl2 + H2O
8. 2(NH4)3PO4-->3N2+O2+12H2+2PO3
a)name products
b)Name the reactant
c)type of reaction
8 answers
Thanks man!!!could u also help me out on #8 thank you sooo much!!
I would like to, but I am not sure under what conditions the reaction indicated in #8 will take place. It involves the dissociation of ammonia into nitrogen and hydrogen. Do you have the source of the equation?
tht is the only info that is given .i don't know wat to do//u helped me on a question yestesday #3 i think u forgot to use STP for that one u, can go and check it over///thanks
#3.
The problem is the question.
Water vapour calculated was for STP.
However, if it was pure water vapour, it would condense to form water, and does not exist any more in vapour form.
On the other hand, if this amount is dissipated in the air as humidity, it can exist at STP.
The problem is the question.
Water vapour calculated was for STP.
However, if it was pure water vapour, it would condense to form water, and does not exist any more in vapour form.
On the other hand, if this amount is dissipated in the air as humidity, it can exist at STP.
8. 2(NH4)3PO4-->3N2+O2+12H2+2PO3
I believe the equation is not exact or not complete.
The left hand side is ammonium triphosphate.
The right hand side is not clear to me if it is nitrogen, oxygen, H+ and PO33+ ions, but they do not balance.
I believe the equation is not exact or not complete.
The left hand side is ammonium triphosphate.
The right hand side is not clear to me if it is nitrogen, oxygen, H+ and PO33+ ions, but they do not balance.
they asked to name the products and type of reaction
tht is all that is given..i don't know
they asked to name the products and type of reaction//thanks
they asked to name the products and type of reaction//thanks