5 An excited state of an atom has an energy level of 2.5 eV. The ground state of this atom is at 1.1 eV. Which is the maximum energy of a photon emitted when an electron moves from the excited state to the ground state? A 1.1 eV B 1.4 eV C 2.5 eV D 3.6 eV

Answer 1

To find the maximum energy of a photon emitted when an electron moves from the excited state to the ground state, we can use the formula:

\( E_{\text{photon}} = E_{\text{excited}} - E_{\text{ground}} \)

Given that the excited state energy level is 2.5 eV and the ground state energy level is 1.1 eV, we can calculate the energy of the emitted photon:

\[ E_{\text{photon}} = 2.5 , \text{eV} - 1.1 , \text{eV} = 1.4 , \text{eV} \]

Thus, the maximum energy of the photon emitted when the electron moves from the excited state to the ground state is 1.4 eV.

The correct answer is B 1.4 eV.