a. Fn = ma = 100 * 2 = 200N = Net force.
Fn=Fap - Ff=200, Fap = Force applied.
250 - Ff = 200,
-Ff = 200 - 250 = -50,
Ff = 50N = Force of friction.
b. Fc = mg = 100kg * 9.8N/kg = 980N =
Force of the crate = Normal force.
c. u = Ff/Fc 50/980 = 0.05 = coefficient of friction.
d. d = Vo*t + 0.5at^2,
d = 0 + 0.5*2*3^2 = 9m.
5.A crate with a mass of 100kg accelerates with a magnitude of 2.0 m/s2 when it is pushed with a 250N.
a.What is magnitude of the force of friction opposing this motion?
b.What is the normal force of the crate?
c.Using a and b, find the coefficient of friction.
d.If the crate starts from rest, find the distance the crate travels in 3s.
1 answer
1 answer