5. A circuit is supplied with 30 VDC and contains three resistors connected in series. The value or R1 is 80Ω, the value of R2 is 1,000Ω , and the value of R3 is 4,200Ω . What is the voltage drop across R2?
A. 5.68 V
B. 2.14 V
C. 4.61 V
D. 6.82 V
I keep coming up with even number 6 and that is not an option. I did everything 4 times. Calculated the total circuit current which came up as 0.006. Did I do that wrong? That's the only thing I can think of where I may have goofed.
Thanks! :)
2 answers
I did it for the zillionth time and came up with 5.68V... Is that correct?
E = 30 Vdc
R1 = 80 Ohms
R2 = 1,000 Ohms
R3 = 4,200 Ohms
V2 = ?
I = E/(R1+R2+R3) = 30/5,280 = 0.00568A
V2 = I * R2 =
R1 = 80 Ohms
R2 = 1,000 Ohms
R3 = 4,200 Ohms
V2 = ?
I = E/(R1+R2+R3) = 30/5,280 = 0.00568A
V2 = I * R2 =
1 answer