Question

5. A bomber is flying at a height of 9 km at 800 km/h. How far in front of the target should he
drop his bombs? show formulas*

Answer 1

800 km/h = 222.2 m/s

Bomb fall time = sqrt(2H/g) = 42.9 s
(neglecting air resistance)

Bomb forward motion during fall time =
42.9*222.2 = 9533 m = 9.53 km

That is the "lead distance"

Answer 2

123.456