I will do one.
1.12121212... is that it? Your indication is not clear.
multiply by 10
12.12121212
subtract 1.12121212
answer 12
12=10n-n=9n
n=12/9
you want to get rid of the repeating decimal.
one more.
.353535.. multipy by 100
35.353535 then subtract .353535
ans: 35
so 35=100n-1n=99n
n= 35/99
5.9(line over it)
0.1515...
1.20(line over it)
0.35(line over it)
0.72(line over it)
1.12(line over it)
need to change these from decimals to fractions, im confused as to how to do it and get the answer, sub teacher taught it different and I am not getting the same answer that is in my book. Im feeling like an idiot because I am not understanding it
3 answers
we are writing a repeating decimal.
example is n=1.21(line over it)
-multiply both sides of the equation by a power of 10 determined by the number of digits in the block of repeating digits; since there are 2 digits that repeat we multiply by 100
-100n=121.21(repeat)
subtract n=1.21
99n=120 n=120/99=40/33
I don't understand how you get 121.12 and where 120 comes from; I understand you subtract 1 from 100 to get 99, but not seeing how you get 120 from 1.21
example is n=1.21(line over it)
-multiply both sides of the equation by a power of 10 determined by the number of digits in the block of repeating digits; since there are 2 digits that repeat we multiply by 100
-100n=121.21(repeat)
subtract n=1.21
99n=120 n=120/99=40/33
I don't understand how you get 121.12 and where 120 comes from; I understand you subtract 1 from 100 to get 99, but not seeing how you get 120 from 1.21
121.212121...
-1.212121...
____________________
120
-1.212121...
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120