I read that as
(5/4)x + (1/8)x
= (11/8)x
or
if you meant ...
5/(4x) + 1/(8x), then
= 10/(8x) + 1/(8x)
= 11/(8x)
or
if you have an equation
(5/4)x + (1/8)x = 3/8 + x
I would multiply each term by 8 and it becomes a very simple equation.
or ....
5/4x + 1/8x = 3/8 + x =
X =
2 answers
The Xs are in the numerator or the de-
nominator
If they are in the numerator, (5/4)x =
5x/4 , and (1/8)x = x/8.
5x/4 + x/8 = 3/8 + x
5x/4 + x/8 - x = 3/8,
Multiply both sides by 8:
10x + x - 8x = 3,
3x = 3,
x = 1.
If the Xs are in the denominator,
5/4x + 1/8x = 3/8 + x.
Multiply both sides by 8x:
1O + 1 = 3x + 8x^2,
8x^2 + 3x - 11 = 0
Factor using A*C method:
A*C = 8*-11 = -88,
8x^2 +11x-8x -11 = 0
Group the 4 terms into factorable pairs
(8x^2 - 8x) + (11x - 11) = 0,
Factor 8x from the 1st pair and
11 from the 2nd 2 pair:
8x(x - 1) + 11(x - 1) = 0,
Factor (x - 1) from each term:
(x - 1) (8x + 11) = 0,
x - 1 = 0, x = 1; 8x + 11 = 0, x = -11/8. S0lution: X = 1, AND X = -11/8.
nominator
If they are in the numerator, (5/4)x =
5x/4 , and (1/8)x = x/8.
5x/4 + x/8 = 3/8 + x
5x/4 + x/8 - x = 3/8,
Multiply both sides by 8:
10x + x - 8x = 3,
3x = 3,
x = 1.
If the Xs are in the denominator,
5/4x + 1/8x = 3/8 + x.
Multiply both sides by 8x:
1O + 1 = 3x + 8x^2,
8x^2 + 3x - 11 = 0
Factor using A*C method:
A*C = 8*-11 = -88,
8x^2 +11x-8x -11 = 0
Group the 4 terms into factorable pairs
(8x^2 - 8x) + (11x - 11) = 0,
Factor 8x from the 1st pair and
11 from the 2nd 2 pair:
8x(x - 1) + 11(x - 1) = 0,
Factor (x - 1) from each term:
(x - 1) (8x + 11) = 0,
x - 1 = 0, x = 1; 8x + 11 = 0, x = -11/8. S0lution: X = 1, AND X = -11/8.