5+4/7(21+3x)=41

Answer 1

To solve the equation \( 5 + \frac{4}{7}(21 + 3x) = 41 \), follow these steps:

1. First, isolate the term with \( x \): \[ \frac{4}{7}(21 + 3x) = 41 - 5 \] \[ \frac{4}{7}(21 + 3x) = 36 \]

2. Next, eliminate the fraction by multiplying both sides by \( 7 \): \[ 4(21 + 3x) = 36 \times 7 \] \[ 4(21 + 3x) = 252 \]

3. Now divide both sides by \( 4 \): \[ 21 + 3x = \frac{252}{4} \] \[ 21 + 3x = 63 \]

4. Subtract \( 21 \) from both sides: \[ 3x = 63 - 21 \] \[ 3x = 42 \]

5. Finally, divide by \( 3 \): \[ x = \frac{42}{3} \] \[ x = 14 \]

So, the solution is \( x = 14 \).