HBr is a strong acid; i.e., it is ionized 100%. Therefore, (H^+) = 5E-3 mols/15.0L = ?M
Then (H^+)(OH^-) = Kw = 1E-14.
You know Kw and you know (H^+), solve for (OH^-)
5.00×10−3mol of HBr are dissolved in water to make 15.0L of solution. What is the concentration of hydroxide ions, [OH−], in this solution?
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