(N2) = mols/L = 5.0 mols/10. L = 0.5 M initial
(O2) = 2.5 mols/10. L = 0.25 M initial
(NO2) = 1.5 mols/10. L = 0.15 M at equilibrium
.............................N2 + 2O2 ==> 2NO2
Initial...................0.5......0.25.........0
change.................-x.........-2x........2x
equilibrium .......0.5-x.....0.25-2x....2x
The problem tells you that 2x = 0.15 M
Knowing x you can calculate 0.5-x and 0.25-2x so now you know the equilibrium concentrations of all three components. Plug those values into Kc expression and solve for Kc. Post your work if you get stuck.
5.0 moles of nitrogen gas is reacted with 2.5 moles of oxygen gas in an 10. L container. At equilibrium, 1.5 moles of nitrogen dioxide is collected. What is the equilibrium constant for the formation of NO2 gas? A. 0.568 b. 0.756 c. 5.29 d. 1.76
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