5.0 mL of H2SO4 solution was titrated with 0.20 M NaOH standard solution. The volume of NaOH needed to reach the equivalent point was 9.5 mL.

Question

1. In this titration setup, what is the titrant? and what is the analyte?
2. What is the number of mole of H2SO4 in the 5.0 mL solution?
3. What is the molarity of H2SO4 solution?
4. What is the mass (g) of H2SO4 in the 5.0 mL solution?
5. What is the mass of sulfur in the 5.0 mL solution?

Answer 1

2NaOH + H2SO4 ==>Na2SO4 + 2H2O
1. The NaOH is the titrant; H2SO4 is the analyte.
2. mols NaOH = M x L
mols H2SO4 = 1/2 mols NaOH (Look at the coefficients in the balanced equation.)
3. M H2SO4 = mols H2SO4/L H2SO4
4. g H2SO4 = mols H2SO4 x molar mass H2SO4
5. mass S = mass H2SO4 x (atomic mass S/molar mass H2SO4) = ?