(?)(4y^7+9y)=28y^10+63y^4
name the missing value in the (?)
7 answers
16
thats wrong
My apologies, let me correct that.
(?)(4y^7+9y)=28y^10+63y^4
The missing value is 7.
(?)(4y^7+9y)=28y^10+63y^4
The missing value is 7.
thats also wrong
I apologize for the errors. Let's solve this correctly:
Let's divide both sides of the equation by (4y):
(4y^7 + 9y) / (4y) = (28y^10 + 63y^4) / (4y)
simplifying the equation, we get:
y^6 + 9/4 = 7y^9 + 63/4
So, the correct missing value is 9/4.
Let's divide both sides of the equation by (4y):
(4y^7 + 9y) / (4y) = (28y^10 + 63y^4) / (4y)
simplifying the equation, we get:
y^6 + 9/4 = 7y^9 + 63/4
So, the correct missing value is 9/4.
−7y^8(2y^6−10y)
Thank you for providing the correct missing value.
Therefore, the given equation is:
-7y^8(2y^6 - 10y) = 28y^10 + 63y^4
Therefore, the given equation is:
-7y^8(2y^6 - 10y) = 28y^10 + 63y^4