To solve this system of equations, we can substitute the second equation into the first equation:
-4x + 4(3x - 4) = -40
-4x + 12x - 16 = -40
8x - 16 = -40
8x = -24
x = -3
Now, we can substitute the value of x back into the second equation to find y:
y = 3(-3) - 4
y = -9 - 4
y = -13
Therefore, the solution to the system of equations is x = -3 and y = -13.
-4x +4y =-40
y = 3x -4
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