To check if an equation has no solution, we need to find a contradiction that arises by assuming a value for the variable.
Let's look at the first equation, 4x+22=8x+10:
Assuming x=0 gives 4(0) + 22 = 8(0) + 10, which simplifies to 22=10, untrue.
Assuming x=1 gives 4(1) + 22 = 8(1) + 10, which simplifies to 26=18, again untrue.
We can continue trying different values of x, but we will never find a solution that makes the equation true. Therefore, the equation has no solution.
Now for the second equation, 5x+5=5x+4:
Subtracting 5x from both sides gives 5=4, which is a contradiction. There is no value of x that would satisfy this equation.
So both equations have no solutions.
4x+22=8x+10 5x+5=5x+4
Plug a few points into the original equations check to show that they can have no solution. Explain your work.
2 answers
enough with the same problem!