4x^2-9y+32x-144y-548=0

Answer 1

4x^2+32x+64 -548+64=144y
4(x+4)^2-484=144y
(x+4)^2-121=38y
the left is a difference of two squares...
(x+4-11)(x+4+11)=38y

check all that I did it in my head.

Answer 2

I'd have stopped a step earlier:

y = (x+4)^2/38 - 121/38