4x^2 - 3x + 3 = 0 Solve by completing the square
4 answers
repeat the procedure I just showed you, tell me what you got.
I divided everything by 4 to get:
x^2 - 3/4x + 3/4 =0
x^2 - 3/4x + 9/64 = -3/4 + 9/64
Here is where I'm stuck
x^2 - 3/4x + 3/4 =0
x^2 - 3/4x + 9/64 = -3/4 + 9/64
Here is where I'm stuck
well, you created the perfect square on the left, so state it , and simplify the right side
(x - 3/8)^2 = -39/64
ahhh, I see the problem.
How can anything squared be negative, so there is no REAL number solution.
Have you studied complex numbers?
If so, then
x - 3/8 = ± i√39/8
x = (3 ± i√39)/8
(x - 3/8)^2 = -39/64
ahhh, I see the problem.
How can anything squared be negative, so there is no REAL number solution.
Have you studied complex numbers?
If so, then
x - 3/8 = ± i√39/8
x = (3 ± i√39)/8
Thanks Reiny - I get stuck on this type of problem every time.
1 answer