4x^2+12 = 0

Question

I factored this out, but how do I show the final answer? Thanks!

4(x^2+3)

Answer 1

4(x²+3)=0
x²=-3
x=sqrt(-3)
=±(sqrt(3)*i)
where i²=-1
The roots are therefore complex.

Answer 2

Would iroot3 and -iroot3 be acceptable answers? Thanks!

Answer 3

Yes, they are acceptable answers.

When in doubt (as in an exam), the best way to check an answer is to square your proposed roots and see if you get back -3.

Answer 4

Thanks for the help!