To solve the equation \(-4x + \frac{19}{8} = 20\), follow these steps:
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Isolate the term with \(x\): \[ -4x = 20 - \frac{19}{8} \]
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Convert 20 to a fraction: Since \(\frac{20}{1}\) can be expressed with an 8 as denominator as follows: \[ 20 = \frac{20 \times 8}{1 \times 8} = \frac{160}{8} \]
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Subtract the fractions: Now we subtract: \[ -4x = \frac{160}{8} - \frac{19}{8} = \frac{160 - 19}{8} = \frac{141}{8} \]
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Divide both sides by -4: To solve for \(x\), divide both sides by -4: \[ x = -\frac{141}{8} \div -4 = \frac{141}{8} \times \frac{1}{-4} = -\frac{141}{32} \]
Thus, the solution is: \[ x = -\frac{141}{32} \]