4s+2b=100

Question

2s+3b=70
Usin elimation

Answer 1

To eliminate the variable "s", we can multiply the first equation by 2 and the second equation by -4, and then add the two equations together.

2(4s+2b) + (-4)(2s+3b) = 2(100) + (-4)(70)

8s + 4b - 8s - 12b = 200 - 280

-8b = -80

Simplifying, we get:

8b = 80

Dividing both sides by 8:

b = 10

Now, substitute this value of b into either of the original equations. Let's use the first equation:

4s + 2(10) = 100

4s + 20 = 100

Subtracting 20 from both sides:

4s = 80

Dividing both sides by 4:

s = 20

So, the solution to the system of equations is s = 20 and b = 10.