4cos^2 theta = 3 where 0 degrees < theta< 360

Answer 1

4cos^2 theta = 3
cos^2 theta = 3/4
cos (theta) = sqrt(3) / 2
theta = arccos [ sqrt(3) / 2 ]

theta = π/6 , 11π/6

hope this helps~ XD

Answer 2

oops i forgot the +/- sign:

cos (theta) = +/- sqrt(3) / 2
theta = +/- arccos [ sqrt(3) / 2 ]

theta = π/6 , 11π/6 , 5π/6 , 7π/6