can you not compute
49/7 28/7 w^5/w and w^3/w?
Just divide each term by 7 and by w.
Hint: when dividing powers, subtract exponents.
(49w^5-28w^3)/7w
6 answers
@Steve How do I divide each term? and then subtract? Its Dividing Binomials by Monomials. It says you have to find the quotient.
Can you please help me? I tried to figure it out. Can you please give me the answer so I can put it on my homework.
My answer is 7w^6-4w^4 it was not correct.
(49w^5-28w^3)/7w=
49w^5/7w - 28w^3/7w
= 7w^4 - 4w^2
Why did you add exponents, when I suggested you need to subtract when dividing?
x^a/x^b = x^(a-b)
49w^5/7w - 28w^3/7w
= 7w^4 - 4w^2
Why did you add exponents, when I suggested you need to subtract when dividing?
x^a/x^b = x^(a-b)
Thank you so much! Now I get Dividing Binomials by Monomials. Just with understanding how to do one of those math problems I got how to do the others. :)