Asked by Anonymous
What is the composition of 21 g NaCl in 500 ml solution (density 1.12 g/ml) in % (w/w)?
1. 0.375%
2. 21.25%
3. 3.75%
4. 4.75%
5. 2.125%
1. 0.375%
2. 21.25%
3. 3.75%
4. 4.75%
5. 2.125%
Answers
Answered by
Maria
answer is % (w/w)
=
21g/(500ml x 1.12 g/ml)
=
21/560
=
3.75%
=
21g/(500ml x 1.12 g/ml)
=
21/560
=
3.75%
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