Asked by Anonymous
what must be the dimensions of a rectangle to have an area of 125 cm^2 and a perimeter of 60 m?
Answers
Answered by
drwls
Solve these two equations simultaneously:
2a + 2b = 60
a*b = 125
Solve by substitution to eliminate one variable:
2a + 250/a = 60
a + 125/a = 30
a^2 -30a +125 = 0
(a -25)(a-5) = 0
a = 5 or 25
If a = 5, b = 25
If a = 25, b = 5
2a + 2b = 60
a*b = 125
Solve by substitution to eliminate one variable:
2a + 250/a = 60
a + 125/a = 30
a^2 -30a +125 = 0
(a -25)(a-5) = 0
a = 5 or 25
If a = 5, b = 25
If a = 25, b = 5